S risk matematicite tuk da me oplyujat, eto kakwo mi kaza "konvencionalnoto sredstwo" Maxima 5.9.0 po twoya wypros :)

(C1) allroots( x^4 + 3*x^3 + 2*x^2 + 2*x + 1 = 0, x );
(D1) [x = 0.82408147191048 %I + 0.02474368089323,

x = 0.02474368089323 - 0.82408147191048 %I, x = - 0.60080930542159,

x = - 2.448678056364867]